Question

Задания на фотографии

Answer 1

27^(-2/3)=1/27^(2/3)=1/3^(6/3)=1/3^2=1/9-верно.
x=1/16, (1/16)^(-1/2)=16^(1/2)=4.

Answer 2

1)$log_{27}frac{1}{9}=log_{3^3}3^{-2}=-frac{2}{3}$
Верно.


2)ОДЗ:
x>0, x≠1
$log_x4=-frac{1}{2}\4=x^{-frac{1}{2}}\4=frac{1}{sqrt{x}}\sqrt{x}=frac{1}{4}\x=frac{1}{16}$


3)
ОДЗ: 
x>0
$log_{27}x=-frac{1}{3}\x=(27)^{-frac{1}{3}}\x=frac{1}{sqrt[3]{27}}\x=frac{1}{3}$