Question

1,6x+x^2=0
Решите уравнение

Answer 1

$x^2+1.6x=0;\ x(x+1.6)=0;\ left [{{x=0;} atop {x+1.6=0;}} right. left [ {{x_1=0;} atop {x_2=-1.6.}} right.$
Ответ:$-1.6; 0.$