Question

Решите уравнение:2x^3+x^2-8x-4=0

Answer 1

(2х^3+х^2)-(8х+4)=0
х^2(2х+1)-4(2х+1)=0
(2х+1)(х^2-4)=0
(2х+1)(х-2)(х+2)=0
2х+1=0
2х=-1
х1=-1/2
х-2=0
х2=2
х+2=0
х3=-2