Question

1.(х+4)^2=x(x+3)
2.10-x(5-(6+x))=x(x+3)-4x

Answer 1

1) x^2+8x+16-x^2-3x=0
5x=-16
x=-3,2

2) 10-x(5-6-x)=x^2+3x-4x
10-x(-1-x)-x^2+x=0
10+x+x^2-x^2+x=0
2x=-10
x=-5