Question

y=(x^2-5x)(1-2кореньx)

Answer 1

y=(x^2-5x)(1-2Vx)

y=x^2-5x-Vx+4

y=x^2-5x-4x

D= (-5)^2-4*1*(-4)=25+16=41

x12= 5+-41/2

x1= 5+41/2=23

x2= 5-41/2=18

Ответ: 23;18