Question

Помогитееее!!!!!!!!!!!!!

Answer 1

$( frac{4}{(x-2)(x+2)}- frac{1}{x-2} )* frac{(x+2)^2}{3}= frac{4-(x+2)}{(x-2)(x+2)}* frac{(x+2)^2}{3} = \ \ = frac{4-x-2}{x-2} * frac{x+2}{3}= frac{2-x}{-(2-x)}* frac{x+2}{3}=- frac{x+2}{3}$

Answer 2

(4/(x²-4) + 1/(2-x)).(x²+4x+4)/3=
=(4/(x+2)(x-2)-1/(x-2)).(x+2)²/3=
=(4-x-2)/(x+2)(x-2) .(x+2)²/3=
=(2-x)/(x-2) . (x+2)/3=-(x-2)/(x-2) .(x+2)/3=
=-(x+2)/3