Question

2cos(П/6-x/2) ≥ tg3П/4 Срочно , помогите.

Answer 1

2cos(П/6-x/2) ≥ tg3П/4 (tg(3П/4)=-1;)

2cos(П/6-x/2)>=-1

cos(П/6-x/2)>-1/2

-2П/3+2Пn<=П/6-x/2<=2П/3+2Пn; n e Z

-2П/3-П/6+2Пn<=-x/2<=2П/3-П/6+2Пn; n e Z 

-5П/6+2Пn<=-x/2<=П/2+2Пn; n e Z  

5П/6-2Пn>=x/2>=-П/2-2Пn; n e Z  

5П/3-4Пn>=x>=-П-4Пn; n e Z