Question

Срочно! Помогите с решение примера $frac{64 b^{2}+128b+64 }{b} : ( frac{4}{b} + 4)$ B= - $frac{15}{16}$

Answer 1

$frac{64b^2 +128b +64}{b} : ( frac{4}{b} +4)= frac{64*(b^2 +2b +1) }{b} :( frac{4+4b}{b} ) = \ \ = frac{64*(b+1)^2}{b} : frac{4(b+1)}{b} = frac{64(b+1)^2}{b} * frac{b}{4(b+1)} = \ \ = frac{16(b+1)*1}{1*1} = 16(b+1) \ \ \ b=- frac{15}{16} \ \ 16*(- frac{15}{16} +1) = 16 * frac{1}{16} = frac{16}{16} = 1$