Question

$\sqrt{4/3} cost=cos^{2}1+sin^{2}1$решите уравнение корень 4/3 cost=cos2t+sin2t

Answer 1

$\sqrt{\frac{4}{3} }cos(t)=cos^2(t) +sin^2(t)\\\sqrt{\frac{4}{3} }cos(t)=1\\cos(t)=\frac{\sqrt{3} }{2} =>x=+-\frac{\pi}{6} +2\pi k$

k∈Z