Question

помоги математику !!!!​

Answer 1

$\sqrt{2}\ tgx + \sqrt{2} = 0\\\\\sqrt{2}(tgx + 1) = 0\ \ \ \ \ \Big| :\sqrt{2}\\\\tgx + 1 = 0\\\\tgx = -1\\\\x = -arctg1 + \pi k\\\\\boxed{x = -\dfrac{\pi}{4} + \pi k}\ ,\ k\in\mathbb{Z}$