Question

РЕШЕНИ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$y = 2 + 4e^{-x} + tg\dfrac{x}{5} - arctg3x\\\\\\y' = 2' + 4(e^{-x})' + \left(tg\dfrac{x}{5}\right)' - (arctg3x)' = 0 + 4\cdot (-1)\cdot e^{-x} + \dfrac{1}{5}\cdot \dfrac{1}{\cos^2\dfrac{x}{5}} -\\\\\\- 3\cdot \dfrac{1}{1+(3x)^2} = \boxed{\bf{-\dfrac{4}{e^x} + \dfrac{1}{5\cos^2\dfrac{x}{5}} - \dfrac{3}{1+9x^2}}}$