Question

помогите пожалуйста срочно без спамов иначе бан​

Answer 1

Ответ:

$981.\ 1)\ \ 15+5x\leq x\ \ \to \ \ 5x-x\leq -15\ \ ,\ \ 4x\leq -15\\\\4x\leq a\ \ \ \Rightarrow \ \ \ \underline {\ a=-15\ }\\\\2)\ \ -9y+27>3\ \ \to \ \ \ 27-3>9y\ \ ,\ \ 9y<24\ \ ,\ \ 3y<8\\\\3y<a\ \ \ \Rightarrow \ \ \underline {\ a=8\ }\\\\3)\ \ 14z+40<41\ \ \to \ \ \ 14z<1\ \ ,\ \ 7z<0,5\\\\7z<a\ \ \ \Rightarrow \ \ \ \underline {\ a=0,5\ }\\\\4)\ \ 63-10t\geq 65\ \ \to \ \ 63-65\geq 10t\ \ ,\ \ -2\geq 10t\ \ ,\ \ 10t\leq -2\ \ ,\ \ 5t\leq -1\\\\5t\leq a\ \ \Rightarrow \ \ \ \underline {\ a=-1\ }$

$982.\ 1)\ \ \dfrac{4}{7} +13x\geq 10x+3\dfrac{4}{7}\ \ ,\ \ 3x\geq 3\\\\2,5x+a\geq 1-0,5x\ \ \to \ \ \ 3x\geq 1-a\\\\1-a=3\ \ ,\ \ \underline {\ a=-2\ }\\\\2)\ \ 19\dfrac{2}{9}\, y-40<20y-55\ \ \to \ \ \ 20y-\dfrac{173}{9}\, y>55-40\ ,\ \ \dfrac{7}{9}\, y>15\\\\\dfrac{2}{9}\, y+7<y+a\ \ \to \ \ y-\dfrac{2}{9}\, y>7-a\ \ ,\ \ \ \dfrac{7}{9}\, y>7-a\\\\7-a=15\ \ ,\ \ \underline{\ a=-8\ }$